2013 Student's Results.

2013 Student's Results.

P3 English - Girl from Endeavour Primary scored 43 out of 50 marks for SA2.

P4 Science - Girl from Endeavour Primary improved from 50 marks in SA1 to 61 marks in SA2.

P5 Maths - Boy from Endeavour Primary improved from 65 marks in SA1 to 89 marks for SA2, with full marks for Paper1.

P5 Maths - Girl from Sembawang Primary scored 76.5 marks for SA2.

P6 Science - Girl from Chongfu Primary scored 60 marks in SA1. Scored a B for PSLE.

P6 Science - Boy from Christian Brother's School scored 86 marks for Prelim. Scored an A for PSLE.
Aggregate of 228 for PSLE.

P6 Maths - Girl from Christian Brother's School scored 79 marks for Prelim. Scored an A for PSLE .

P6 Maths - Girl from Christian Brother's School scored 84.5 marks for Prelim. Scored an A* for PSLE . Aggregate of 255 for PSLE.

P6 Maths - Girl from Chongfu Primary scored 67.5 marks in SA1. Scored an A for PSLE.

P6 Maths - Boy from Endeavour Primary scored 32 marks in SA1. Scored a B for PSLE.

P6 English - Boy from Wellington Primary scored 42 marks for Paper2 in SA1. Scored a B for PSLE.

P6 English - Girl from Endeavour Primary scored 59.5 marks for Paper 2 in SA1. Scored an A for PSLE.

Sec 1 Maths - Boy from Si Ling Secondary scored 89.5 marks for SA2.

Sec 1 IP Maths - Boy from Hwa Chong Instituition scored As for the first 3 sesmesters' tests. Do not have to take year end exams for Maths.

Sec2 IP English - Boy from Hwa Chong Institution improved from a C5 in 2012 to a B4 in 2013.

Sec3 English - Boy from Canberra Secondary scored an A for SA2.

Sec3 EMaths - Boy from Queenstown Secondary scored 77 marks for SA1, 74 marks for SA2.

Sec4 AMaths - Boy from Catholic High School scored an A for Prelims. Now waiting for O level results.

Sec4 EMaths - Boy from Catholic High School scored an A for Prelims. Now waiting for O level results.

P4 MATHS - Fractions

The number of girls in a school was 2/5 of the number of pupils in the school. There were 48 more boys than girls. After some girls
went for a camp, the number of boys in the school was 4 times the number of the remaining girls. How many girls went camping?

To start off,

the student must know that since 2/5 of the pupils are girls, 3/5 must be boys.

1 - 2/5 = 3/5

We change the fraction to 2 units for girls, and 3 units for boys.

1 unit ---> 48
3 units ---> 48 * 3 = 144 ( Boys )
2 units ---> 48 * 2 = 96 ( Girls)


After, some girls went for a camp, the student must know that the number of boys remained unchanged.

Since the boys now become 4 times the number of girls,

144 / 4 = 38 ( girls now)

96 - 38 = 58 ( girls that went camping )

December Classes have started!

Hi all,

our tuition classes for Year 2013 at Block 487 Admiralty Link have started. Please call to enquire. By the way, I have not posted the year end results of my students yet because ... I just got back from my 3 week reservice in the SAF. Hope to hear from you soon :)

Rgds,
Kenny Wong

P6 Maths - Fractions

Wendy cleaned 1/6 of a room in 2h. Lenna cleaned 1/3 of the same room in 1/2h. If they worked together, how long do they need to clean the room?

For this question, we need to find the 'speed' that they cleaned the room in the same unit of time. Let's use 1 hour here.

Wendy -> 2h -> 1/6 room
-------> 1h -> 1/6 divided by 2 = 1/6 x 1/2 = 1/12 room

Lenna -> 1/2h -> 1/3 room
-------> 1 h -> 1/3 x 2 = 2/3 room

Together -> 1h -> 1/12 + 2/3 = 3/4 room

Room is taken as 1 whole.

Time taken to clean room = 1 divided by 3/4 = 4/3h = 1&1/3h

P6 Maths - Volume

Water drain out from Tap A into 2 containers at 800 cm3 per minute such that the height of water in the 2 containers is the same. The base area of the 2 containers are 500 cm3 and 300 cm3. What will be the height of the water level in the 2 containers after 20 minute?

This question requires a bit of algebra. Also, the student should be able to get the answer by " Guess & Check " method.

Total volume of water from tap A in 20 minutes = 800 x 20 = 16000

Volume of water in 2 containers --> 500 x height + 300 x height = 16000
--> 800 x height = 16000
height = 16000 / 800 = 20cm

P6 Maths - Whole Numbers, Fractions

Mr Lee spent $5190 on some watches and clocks. The amount spent on watches was $2310 more than the amount spent on clocks. He bought 4/5 times as many clocks as watches.
Each clock cost $13 less than each watch. What was the total number of watches and clocks bought by Mr Lee?

Amount spent on clocks = (5190 - 2310)/ 2 = 1440

Amount spent on watches = 1440 + 2310 = 3750

Most students should be able to do the above steps.

The important thing is to find the cost of 1 unit of both watches and clocks for comparison.



4/5 as many clocks as watches means clocks equal to 4 units while watches equal to 5 units.

Cost of 1 unit of clocks = 1440 / 4 = 360
Cost of 1 unit of watches = 3750 / 5 = 750
Difference between 1 unit of clock and watches = 750-360 = 390

Number of watches or clocks in 1 unit = 390 / 13 = 30

Hence total ( 9 units of clocks and watches ) = 9 x 30 = 270

P6 Maths - Percentage

Cathy has $3600 more money than Bob. 60% of Bob’s money is equal to 15% of Cathy’s money.
How much money does Cathy has?

For some questions, to see the picture more clearly, its better to change the percentage to fraction.

60/100 of Bob’s money = 15/100 of Cathy

Then we make the numerator the same,

60/100 of Bob’s money = 60/400 of Cathy

Taking the denominator, we now know that Bob has 100 units while Cathy has 400 units.

Difference = 400 – 100 = 300 units

300 units --> $3600

100 units --> 3600 / 3 = $1200

400 units --> 1200 * 4 = $4800 (Cathy)